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    NEW QUESTION 25
    The code block shown below should return a one-column DataFrame where the column storeId is converted to string type. Choose the answer that correctly fills the blanks in the code block to accomplish this.
    transactionsDf.__1__(__2__.__3__(__4__))

    • A. 1. select
      2. col("storeId")
      3. cast
      4. StringType()
    • B. 1. select
      2. col("storeId")
      3. as
      4. StringType
    • C. 1. select
      2. col("storeId")
      3. cast
      4. StringType
    • D. 1. select
      2. storeId
      3. cast
      4. StringType()
    • E. 1. cast
      2. "storeId"
      3. as
      4. StringType()

    Answer: A

    Explanation:
    Explanation
    Correct code block:
    transactionsDf.select(col("storeId").cast(StringType()))
    Solving this question involves understanding that, when using types from the pyspark.sql.types such as StringType, these types need to be instantiated when using them in Spark, or, in simple words, they need to be followed by parentheses like so: StringType(). You could also use .cast("string") instead, but that option is not given here.
    More info: pyspark.sql.Column.cast - PySpark 3.1.2 documentation
    Static notebook | Dynamic notebook: See test 2

     

    NEW QUESTION 26
    Which of the following code blocks returns a DataFrame showing the mean value of column "value" of DataFrame transactionsDf, grouped by its column storeId?

    • A. transactionsDf.groupBy(col(storeId).avg())
    • B. transactionsDf.groupBy("storeId").avg(col("value"))
    • C. transactionsDf.groupBy("storeId").agg(average("value"))
    • D. transactionsDf.groupBy("storeId").agg(avg("value"))
    • E. transactionsDf.groupBy("value").average()

    Answer: D

    Explanation:
    Explanation
    This question tests your knowledge about how to use the groupBy and agg pattern in Spark. Using the documentation, you can find out that there is no average() method in pyspark.sql.functions.
    Static notebook | Dynamic notebook: See test 2

     

    NEW QUESTION 27
    The code block displayed below contains an error. When the code block below has executed, it should have divided DataFrame transactionsDf into 14 parts, based on columns storeId and transactionDate (in this order). Find the error.
    Code block:
    transactionsDf.coalesce(14, ("storeId", "transactionDate"))

    • A. Operator coalesce needs to be replaced by repartition, the parentheses around the column names need to be removed, and .select() needs to be appended to the code block.
    • B. Operator coalesce needs to be replaced by repartition, the parentheses around the column names need to be removed, and .count() needs to be appended to the code block.
      (Correct)
    • C. Operator coalesce needs to be replaced by repartition and the parentheses around the column names need to be replaced by square brackets.
    • D. Operator coalesce needs to be replaced by repartition.
    • E. The parentheses around the column names need to be removed and .select() needs to be appended to the code block.

    Answer: B

    Explanation:
    Explanation
    Correct code block:
    transactionsDf.repartition(14, "storeId", "transactionDate").count()
    Since we do not know how many partitions DataFrame transactionsDf has, we cannot safely use coalesce, since it would not make any change if the current number of partitions is smaller than 14.
    So, we need to use repartition.
    In the Spark documentation, the call structure for repartition is shown like this:
    DataFrame.repartition(numPartitions, *cols). The * operator means that any argument after numPartitions will be interpreted as column. Therefore, the brackets need to be removed.
    Finally, the question specifies that after the execution the DataFrame should be divided. So, indirectly this question is asking us to append an action to the code block. Since .select() is a transformation. the only possible choice here is .count().
    More info: pyspark.sql.DataFrame.repartition - PySpark 3.1.1 documentation Static notebook | Dynamic notebook: See test 1

     

    NEW QUESTION 28
    The code block shown below should return a column that indicates through boolean variables whether rows in DataFrame transactionsDf have values greater or equal to 20 and smaller or equal to
    30 in column storeId and have the value 2 in column productId. Choose the answer that correctly fills the blanks in the code block to accomplish this.
    transactionsDf.__1__((__2__.__3__) __4__ (__5__))

    • A. 1. select
      2. col("storeId")
      3. between(20, 30)
      4. and
      5. col("productId")==2
    • B. 1. select
      2. col("storeId")
      3. between(20, 30)
      4. &&
      5. col("productId")=2
    • C. 1. select
      2. "storeId"
      3. between(20, 30)
      4. &&
      5. col("productId")==2
    • D. 1. where
      2. col("storeId")
      3. geq(20).leq(30)
      4. &
      5. col("productId")==2
    • E. 1. select
      2. col("storeId")
      3. between(20, 30)
      4. &
      5. col("productId")==2

    Answer: B

    Explanation:
    Explanation
    Correct code block:
    transactionsDf.select((col("storeId").between(20, 30)) & (col("productId")==2)) Although this question may make you think that it asks for a filter or where statement, it does not. It asks explicity to return a column with booleans - this should point you to the select statement.
    Another trick here is the rarely used between() method. It exists and resolves to ((storeId >= 20) AND (storeId
    <= 30)) in SQL. geq() and leq() do not exist.
    Another riddle here is how to chain the two conditions. The only valid answer here is &. Operators like && or and are not valid. Other boolean operators that would be valid in Spark are | and.
    Static notebook | Dynamic notebook: See test 1

     

    NEW QUESTION 29
    ......