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    Juniper Service Provider, Professional (JNCIP-SP) JN0-664 Prüfungsfragen mit Lösungen (Q39-Q44):

    39. Frage
    Exhibit
    user@Rl show configuration interpolated-profile { interpolate {
    fill-level [ 50 75 drop-probability [ > }
    class-of-service drop-profiles
    ];
    20 60 ];
    Which two statements are correct about the class-of-service configuration shown in the exhibit? (Choose two.)

    • A. To use this drop profile, you reference it in a scheduler.
    • B. The drop probability jumps immediately from 20% to 60% when the queue level reaches 75% full.
    • C. To use this drop profile, you apply it directly to an interface.
    • D. The drop probability gradually increases from 20% to 60% as the queue level increases from 50% full to
      75% full

    Antwort: A,D

    Begründung:
    Explanation
    class-of-service (CoS) is a feature that allows you to prioritize and manage network traffic based on various criteria, such as application type, user group, or packet loss priority. CoS uses different components to classify, mark, queue, schedule, shape, and drop traffic according to the configured policies.
    One of the components of CoS is drop profiles, which define how packets are dropped when a queue is congested. Drop profiles use random early detection (RED) algorithm to drop packets randomly before the queue is full, which helps to avoid global synchronization and improve network performance. Drop profiles can be discrete or interpolated. A discrete drop profile maps a specific fill level of a queue to a specific drop probability. An interpolated drop profile maps a range of fill levels of a queue to a range of drop probabilities and interpolates the values in between.
    In the exhibit, we can see that the class-of-service configuration shows an interpolated drop profile with two fill levels (50 and 75) and two drop probabilities (20 and 60). Based on this configuration, we can infer the following statements:
    * The drop probability jumps immediately from 20% to 60% when the queue level reaches 75% full. This is not correct because the drop profile is interpolated, not discrete. This means that the drop probability gradually increases from 20% to 60% as the queue level increases from 50% full to 75% full. The drop probability for any fill level between 50% and 75% can be calculated by using linear interpolation formula.
    * The drop probability gradually increases from 20% to 60% as the queue level increases from 50% full to
    75% full. This is correct because the drop profile is interpolated and uses linear interpolation formula to calculate the drop probability for any fill level between 50% and 75%. For example, if the fill level is
    60%, the drop probability is 28%, which is calculated by using the formula: (60 - 50) / (75 - 50) * (60 -
    20) + 20 = 28.
    * To use this drop profile, you reference it in a scheduler. This is correct because a scheduler is a component of CoS that determines how packets are dequeued from different queues and transmitted on an interface. A scheduler can reference a drop profile by using the random-detect statement under the
    [edit class-of-service schedulers] hierarchy level. For example: scheduler test { transmit-rate percent 10; buffer-size percent 10; random-detect test-profile; }
    * To use this drop profile, you apply it directly to an interface. This is not correct because a drop profile cannot be applied directly to an interface. A drop profile can only be referenced by a scheduler, which can be applied to an interface by using the scheduler-map statement under the [edit class-of-service interfaces] hierarchy level. For example: interfaces ge-0/0/0 { unit 0 { scheduler-map test-map; } }


    40. Frage
    Exhibit

    The network shown in the exhibit is based on IS-IS
    Which statement is correct in this scenario?

    • A. The area address is two bytes.
    • B. The NSEL byte for Area 0001 is 00.
    • C. The routers are using unnumbered interfaces
    • D. The system IDofR1_2 is 192.168.16.1

    Antwort: B

    Begründung:
    Explanation
    IS-IS is an interior gateway protocol that uses link-state routing to exchange routing information among routers within a single autonomous system. IS-IS uses two types of addresses to identify routers and areas:
    system ID and area address. The system ID is a unique identifier for each router in an IS-IS domain. The system ID is 6 octets long and can be derived from the MAC address or manually configured. The area address is a variable-length identifier for each area in an IS-IS domain. The area address can be 1 to 13 octets long and is composed of high-order octets of the address. An IS-IS instance may be assigned multiple area addresses, which are considered synonymous. Multiple synonymous area addresses are useful when merging or splitting areas in the domain1. In this question, we have a network based on IS-IS with four routers (R1_1, R1_2, R2_1, and R2_2) belonging to area 0001. The area address for area 0001 is 49.0001. The NSEL byte for area 0001 is the last octet of the address, which is 01. The NSEL byte stands for Network Service Access Point Selector (NSAP Selector) and indicates the type of service requested from the network layer2. Therefore, the correct statement in this scenario is that the NSEL byte for area 0001 is 01.
    References: 1:
    https://www.cisco.com/c/en/us/td/docs/ios-xml/ios/iproute_isis/configuration/xe-16/irs-xe-16-book/irs-ovrvw-cf.
    2:
    https://www.juniper.net/documentation/us/en/software/junos/is-is/topics/concept/is-is-routing-overview.html


    41. Frage
    Exhibit

    You must ensure that the VPN backbone is preferred over the back door intra-area link as long as the VPN is available. Referring to the exhibit, which action will accomplish this task?

    • A. Enable OSPF traffic-engineering.
    • B. Create an OSPF sham link between the PE routers.
    • C. Configure the OSPF metric on the backup intra-area link that is higher than the L3VPN link.
    • D. Configure an import routing policy on the CE routers that rejects OSPF routes learned on the backup intra-area link.

    Antwort: B

    Begründung:
    Explanation
    A sham link is a logical link between two PE routers that belong to the same OSPF area but are connected through an L3VPN. A sham link makes the PE routers appear as if they are directly connected, and prevents OSPF from preferring an intra-area back door link over the VPN backbone. To create a sham link, you need to configure the local and remote addresses of the PE routers under the [edit protocols ospf area area-id] hierarchy level1.


    42. Frage
    Exhibit

    You want Site 1 to access three VLANs that are located in Site 2 and Site 3 The customer-facing interface on the PE-1 router is configured for Ethernet-VLAN encapsulation.
    What is the minimum number of L2VPN routing instances to be configured to accomplish this task?

    • A. 0
    • B. 1
    • C. 2
    • D. 3

    Antwort: A

    Begründung:
    Explanation
    To allow Site 1 to access three VLANs that are located in Site 2 and Site 3, you need to configure three L2VPN routing instances on PE-1, one for each VLAN. Each L2VPN routing instance will have a different VLAN ID and a different VNI for VXLAN encapsulation. Each L2VPN routing instance will also have a different vrf-target export value to identify which VPN routes belong to which VLAN. This way, PE-1 can forward traffic from Site 1 to Site 2 and Site 3 based on the VLAN tags and VNIs.


    43. Frage
    Which statement is correct about IS-IS when it performs the Dijkstra algorithm?

    • A. The local router moves its own local tuples into the candidate database
    • B. When a new neighbor ID in the tree database matches a router ID in the LSDB, the neighbor ID is moved to the candidate database
    • C. Tuples with the lowest cost are moved from the tree database to the LSDB.
    • D. The algorithm will stop processing once the tree database is empty.

    Antwort: A

    Begründung:
    Explanation
    IS-IS is a link-state routing protocol that uses the Dijkstra algorithm to compute the shortest paths between nodes in a network. The Dijkstra algorithm maintains three data structures: a tree database, a candidate database, and a link-state database (LSDB). The tree database contains the nodes that have been visited and their shortest distances from the source node. The candidate database contains the nodes that have not been visited yet and their tentative distances from the source node. The LSDB contains the topology information of the network, such as the links and their costs.
    The Dijkstra algorithm works as follows:
    * The local router moves its own local tuples into the tree database. A tuple consists of a node ID, a distance, and a parent node ID. The local router's tuple has a distance of zero and no parent node.
    * The local router moves its neighbors' tuples into the candidate database. The neighbors' tuples have distances equal to the costs of the links to them and parent node IDs equal to the local router's node ID.
    * The local router selects the tuple with the lowest distance from the candidate database and moves it to the tree database. This tuple becomes the current node.
    * The local router updates the distances of the current node's neighbors in the candidate database by adding the current node's distance to the link costs. If a shorter distance is found, the parent node ID is also updated.
    * The algorithm repeats steps 3 and 4 until either the destination node is reached or the candidate database is empty.


    44. Frage
    ......

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