Tema
Desenvolveu um pequeno modelo tridimensional de forma a transmitir a um cliente o aspecto que o seu produto final irá possuir. Pretende criar uma pequena animação de forma a mostrar ao cliente qual o resultado final do projecto.
Solução
Nos passos seguintes irá verificar a facilidade e rapidez com que poderá criar uma animação a partir de AutoCAD 2007. A nova paleta Dashboard, para além dos comandos 2D mais utilizados, contém as ferramentas 3D que lhe permitem trabalhar, desde a criação e edição 3D até às animações, em “projecto-modelo” de uma forma simples, intuitiva e rápida.
Utilize o seguinte ficheiro para este exercício:
Ficheiro: TP060705.dwg
Dimensão do Ficheiro: 193 Kb
Na paleta Dashboard localize o painel 3D Navigate;
Na paleta Dashboard seleccione a vista Southeast Isometric;
Descongele o layer Câmara;
Amplie o desenho de forma a visualizá-lo na sua totalidade;
Na paleta Dashboard seleccione a Perspective Projection;
A partir do menu View seleccione Motion Path Animations e:
Seleccione a opção Link camera to: > Path e seleccione a linha de cor vermelha no desenho;
Seleccione OK para aceitar o nome do caminho;
Seleccione a opção Link target to: > Point e seleccione um ponto no centro do modelo (aproximadamente);
Seleccione OK para aceitar o nome do caminho;
Defina o valor de Frame rate (FPS) para 10 e o valor de Duration (seconds) para 10;
Seleccione o botão Preview;
Na janela Preview seleccione Conceptual e seleccione o botão Play;
Repita o passo anterior alternando de estilo visual;
Feche a janela Preview;
Na janela de diálogo Motion Path Animation:
Abra a lista Visual style e seleccione o estilo visual pretendido;
Seleccione o formato WMV e a resolução 320 x 240;
Active as opções Corner deceleration e Reverse;
Seleccione o botão OK;
Grave a sua animação no seu computador;
A partir do Explorador do Windows localize o seu ficheiro e veja o resultado final!
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Under this circumstance, we know as long as m (the point theta) fulfills sin2m=-1, it is the arrangement and now 2m= 3*pi/2 + 2*k*pi, k is a whole number; so m=3*pi/4 + k*pi, k is a number;
UNIT CIRCLE CHART we presently observe that the terminal side of m is the bisector of the second (II) and fourth (IV) quadrant, if in the second quadrant, sinm=sqrt(2)/2 and cosm= - sqrt(2)/2; we have sinm
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